5v^2=29v+6

Solution for 5v^2=29v+6 equation:

5v^2=29v+6

We move all terms to the left:

5v^2-(29v+6)=0

We get rid of parentheses

5v^2-29v-6=0

a = 5; b = -29; c = -6;
Δ = b2-4ac
Δ = -292-4·5·(-6)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-31}{2*5}=\frac{-2}{10}
=-1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+31}{2*5}=\frac{60}{10}
=6
$